[tex] \left \{ {{ \frac{x}{3}- \frac{2y}{5}=-3} \atop {y-3x=1}} \right. \\ \\ y= 1+3x \\ \\ \frac{x}{3}- \frac{2y}{5}=-3}\ reemplazamos \to { \frac{x}{3}- \frac{2(1+3x)}{5}=-3} \\ \\ { \frac{x}{3}- \frac{2+6x}{5}=-3} \\ \\ { \frac{x}{3}- \frac{2}{5}- \frac{6x}{5}=-3} \\ \\ { \frac{x}{3}- \frac{6x}{5}=-3+ \frac{2}{5} } \\ \\ { \frac{5x}{15}- \frac{18x}{15}= \frac{-15+2}{5} } \\ \\ { - \frac{13x}{5}= \frac{-13}{5} } \to x= 1\\ \\ [/tex]
[tex]y= 1+3x\to y=1+3(1)\to y = 1+3\to y= 4[/tex]
[tex]Solucion \ del \ sistema \ es \ {(1;4)}[/tex]
Espero que te sirva, salu2!!!!
