Explicación paso a paso:
HOLA!
teorema de PITAGORAS encontrar un lado
[tex] {x}^{2} = {5}^{2} + {6}^{2} [/tex]
[tex] {x}^{2} = 25 + 36[/tex]
[tex] {x}^{2} = 61[/tex]
[tex]x = \sqrt{61} [/tex]
[tex]x = 7.81[/tex]
4/
[tex] {37}^{2} = {35}^{2} + {x}^{2} [/tex]
[tex]1369 = 1225 + {x}^{2} [/tex]
[tex]1369 - 1225 = {x}^{2} [/tex]
144= x^ 2
√144= x
12= x
5/
x^2 = 8^2 + 15^2
x^2 = 64+225
x^2 = 289
x= √ 289
x= 17
espero te sirva saludos
