Respuesta:
[tex] \frac{a + ab - b}{b} = [/tex]
[tex] \frac{a}{b} + \frac{ab}{b} - \frac{b}{b} = [/tex]
[tex] \frac{a}{b} + a - 1[/tex]
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[tex] \frac{4 {x}^{2} {y}^{6} - 8 {y}^{3} {x}^{4} + 24 {x}^{3} {y}^{2} }{ - 4 {x}^{2} {y}^{3} } = [/tex]
[tex] - \frac{4 {x}^{2} {y}^{6} - 8 {y}^{3} {x}^{4} + 24 {x}^{3} {y}^{2} }{ 4 {x}^{2} {y}^{3} } [/tex]
[tex] - \frac{4 {x}^{2} {y}^{2} ( {y}^{4} - 2y {x}^{2} + 6x) }{ 4 {x}^{2} {y}^{3} } [/tex]
[tex] - \frac{4 {x}^{2} {y}^{2} ( {y}^{4} - 2y {x}^{2} + 6x) }{ 4 {x}^{2} {y}^{2}y } [/tex]
[tex] - \frac{( {y}^{4} - 2y {x}^{2} + 6x) }{ y } [/tex]
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[tex] \frac{2 {a}^{2} {c}^{3} + 4ab - 6 {a}^{2} {b}^{2} c }{2a {b}^{2} c} [/tex]
[tex] \frac{ 2a(a {c}^{3} + 2b - 3a {b}^{2}c ) }{2a {b}^{2} c} = [/tex]
[tex]\frac{ 2a(a {c}^{3} + 2b - 3a {b}^{2}c ) }{(2a)( {b}^{2} c)} =[/tex]
[tex]\frac{ a {c}^{3} + 2b - 3a {b}^{2}c }{ {b}^{2} c} [/tex]