triangulo de pascal:
................1...................
...........1....2.....1...........
......1......3.....3......1.......
...1.....4......6.....4......1...
.1....5....10.....10....5.....1...
La ultima fila se encontrado los coeficientes de ( x - (1/2)y ) ^5
( x - (1/2)y )^5= x^5 - (5)x^4*(1/2y) + (10) x^3(1/2y)^2 - (10)(x^2)(1/2y)^3 + (5)(x)(1/2y)^4 - x^0(1/2y)^5
..............= x^5 - 5/2(x^4*y) + 5/2(x^3*y^2) - 5/4(x^2*y^3) + 5/16(x*y^4) - (1/32)(y^5)
saludos.
renedescartes.
