a)
[tex]4(3x + 2) = 5x + 6[/tex]
[tex]12x + 8 = 5x + 6[/tex]
[tex]7x = -2[/tex]
[tex]x = \frac{-2}{7} [/tex]
b)
[tex](10x + 20)(-5x + 2) = 0[/tex]
Aqui hay dos soluciones:
- Primera solucion:
[tex]10x + 20 = 0[/tex]
[tex]10x = -20[/tex]
[tex]x= \frac{-20}{10} [/tex]
[tex]x = -2[/tex]
- Segunda solución:
[tex]-5x + 2 = 0[/tex]
[tex]5x = 2[/tex]
[tex]x = \frac{2}{5} [/tex]
c)
[tex]25 x^{2} - 100 = 0[/tex]
[tex]25 x^{2} = 100[/tex]
[tex] x^{2} = 4[/tex]
[tex]x = 2[/tex]
